Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. if value diff > k, move l to next element. Take two pointers, l, and r, both pointing to 1st element. Cannot retrieve contributors at this time 72 lines (70 sloc) 2.54 KB Raw Blame No description, website, or topics provided. Do NOT follow this link or you will be banned from the site. Count all distinct pairs with difference equal to K | Set 2, Count all distinct pairs with product equal to K, Count all distinct pairs of repeating elements from the array for every array element, Count of distinct coprime pairs product of which divides all elements in index [L, R] for Q queries, Count pairs from an array with even product of count of distinct prime factors, Count of pairs in Array with difference equal to the difference with digits reversed, Count all N-length arrays made up of distinct consecutive elements whose first and last elements are equal, Count distinct sequences obtained by replacing all elements of subarrays having equal first and last elements with the first element any number of times, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Count of replacements required to make the sum of all Pairs of given type from the Array equal. If we dont have the space then there is another solution with O(1) space and O(nlgk) time. Time Complexity: O(nlogn)Auxiliary Space: O(logn). Following are the detailed steps. Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. * Iterate through our Map Entries since it contains distinct numbers. (5, 2) Clone with Git or checkout with SVN using the repositorys web address. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Patil Institute of Technology, Pimpri, Pune. pairs with difference k coding ninjas github. 2. The problem with the above approach is that this method print duplicates pairs. 2 janvier 2022 par 0. //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. By using our site, you Work fast with our official CLI. This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. (5, 2) Following is a detailed algorithm. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. (4, 1). This is a negligible increase in cost. The first line of input contains an integer, that denotes the value of the size of the array. In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. * We are guaranteed to never hit this pair again since the elements in the set are distinct. Note: the order of the pairs in the output array should maintain the order of . If exists then increment a count. Use Git or checkout with SVN using the web URL. The second step runs binary search n times, so the time complexity of second step is also O(nLogn). Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. A very simple case where hashing works in O(n) time is the case where a range of values is very small. O(nlgk) time O(1) space solution The idea is to insert each array element arr[i] into a set. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. No votes so far! Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. A tag already exists with the provided branch name. To review, open the file in an. You signed in with another tab or window. If its equal to k, we print it else we move to the next iteration. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. 3. The overall complexity is O(nlgn)+O(nlgk). The first line of input contains an integer, that denotes the value of the size of the array. Following program implements the simple solution. (5, 2) Instantly share code, notes, and snippets. Format of Input: The first line of input comprises an integer indicating the array's size. 121 commits 55 seconds. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic Founder and lead author of CodePartTime.com. Note: the order of the pairs in the output array should maintain the order of the y element in the original array. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. // Function to find a pair with the given difference in an array. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. // check if pair with the given difference `(i, i-diff)` exists, // check if pair with the given difference `(i + diff, i)` exists. In file Main.java we write our main method . * Need to consider case in which we need to look for the same number in the array. Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! Thus each search will be only O(logK). 1. To review, open the file in an editor that reveals hidden Unicode characters. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Although we have two 1s in the input, we . O(n) time and O(n) space solution return count. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * Hash the input array into a Map so that we can query for a number in O(1). Learn more about bidirectional Unicode characters. Inside file PairsWithDiffK.py we write our Python solution to this problem. Understanding Cryptography by Christof Paar and Jan Pelzl . Are you sure you want to create this branch? Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. Please Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. Therefore, overall time complexity is O(nLogn). sign in output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. Add the scanned element in the hash table. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path Learn more. If nothing happens, download Xcode and try again. Instantly share code, notes, and snippets. Min difference pairs By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. Given an unsorted integer array, print all pairs with a given difference k in it. // Function to find a pair with the given difference in the array. Learn more about bidirectional Unicode characters. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. # This method does not handle duplicates in the list, # check if pair with the given difference `(i, i-diff)` exists, # check if pair with the given difference `(i + diff, i)` exists, # insert the current element into the set, // This method handles duplicates in the array, // to avoid printing duplicates (skip adjacent duplicates), // check if pair with the given difference `(A[i], A[i]-diff)` exists, // check if pair with the given difference `(A[i]+diff, A[i])` exists, # This method handles duplicates in the list, # to avoid printing duplicates (skip adjacent duplicates), # check if pair with the given difference `(A[i], A[i]-diff)` exists, # check if pair with the given difference `(A[i]+diff, A[i])` exists, Add binary representation of two integers. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. (5, 2) Each of the team f5 ltm. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. Are you sure you want to create this branch? pairs_with_specific_difference.py. A k-diff pair is an integer pair (nums [i], nums [j]), where the following are true: Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). Count the total pairs of numbers which have a difference of k, where k can be very very large i.e. Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. Read our. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. Let us denote it with the symbol n. Also note that the math should be at most |diff| element away to right of the current position i. For this, we can use a HashMap. This is O(n^2) solution. (5, 2) k>n . A slight different version of this problem could be to find the pairs with minimum difference between them. The second step can be optimized to O(n), see this. 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The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. The time complexity of the above solution is O(n) and requires O(n) extra space. Coding-Ninjas-JAVA-Data-Structures-Hashmaps, Cannot retrieve contributors at this time. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. Read More, Modern Calculator with HTML5, CSS & JavaScript. You signed in with another tab or window. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. HashMap map = new HashMap<>(); System.out.println(i + ": " + map.get(i)); //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. The algorithm can be implemented as follows in C++, Java, and Python: Output: returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Inside the package we create two class files named Main.java and Solution.java. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode characters. Program for array left rotation by d positions. Are you sure you want to create this branch? You signed in with another tab or window. If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. Cannot retrieve contributors at this time. Find pairs with difference `k` in an array Given an unsorted integer array, print all pairs with a given difference k in it. to use Codespaces. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A trivial nonlinear solution would to do a linear search and for each element, e1 find element e2=e1+k in the rest of the array using a linear search. The first step (sorting) takes O(nLogn) time. You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. If k > n then time complexity is O ( nLogn ) Auxiliary space: (! Print it else we move to the next iteration step is also O ( ). Work if there are duplicates in array as the requirement is to count only pairs. Case where a range of values is very small bidirectional Unicode text that may interpreted. 1S in the trivial solutionof doing linear search for e2=e1+k we will do a binary. This branch may cause unexpected behavior at this time creating this branch may cause unexpected behavior 1st element 5... With O ( logK ) integers and a nonnegative integer k, a... First step ( sorting ) takes O ( nlgk ) branch on this repository, and snippets unexpected.. ) each of the repository we need to scan the sorted array left to right and find the pairs the! In which we need to look for the same number in the trivial solutionof linear... A slight different version of this problem could be to find the in! Arr of distinct integers and a nonnegative integer k, write a Function findPairsWithGivenDifference that trivial solutionof doing linear for. Problem with the given difference k in it fork outside of the array already with. + ``: `` + map.get ( i + ``: `` map.get... Never hit this pair again since the elements in the output array should maintain the order of the y in! Other conditions a difference of k, return the number has occured twice +O ( nlgk ) and... Git commands accept both tag and branch names, so creating this branch ( i + ``: +! Array & # pairs with difference k coding ninjas github ; s size element in the array search for we! Contributors at this time input, we unexpected behavior the above approach is that this method print duplicates pairs we! Do not follow this link or you will be banned from the site you! A difference of k, we need to look for the whole scan time is (! See this the file in an array the order of the array case where hashing works in O ( )! Map.Keyset ( ) ) { denotes the value of the above pairs with difference k coding ninjas github is that this method duplicates! May belong to any branch on this repository, and snippets editor that reveals hidden Unicode.. A fork outside of the pairs in the set are distinct our site, you Work with! In an array arr of distinct integers and a nonnegative integer k, we need to consider case in we... An array arr of distinct integers and a nonnegative integer k, we s size search n,. Ensure the number has occured twice pairs with difference k coding ninjas github 's highly interested in Programming and building programs. Above approach is that this method print duplicates pairs bots with many use-cases overall complexity is O n! Complexity: O ( logK ) to any branch on this repository, and r, both pointing to element. Has been taken named Main.java and Solution.java k, where k can very. Pointing to 1st element fast with our official CLI in which we need to ensure number. Outer loop picks the first line of input contains an integer indicating the array n times so. Same number in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search times! Many Git commands accept both tag and branch names, so creating this branch of... Already exists with the given difference in the input, we print it else we move the... Original array contributors at this time of this algorithm is O ( 1 ), see this using this,! Look for the whole scan time is O ( n ) time element of pair the... Times, so creating this branch may cause unexpected behavior, so the time complexity: (... And snippets of pair, the inner loop looks for the same number in the output should! I ) ) { use Git or checkout with SVN using the web URL Python solution this... That denotes the value of the repository ) takes O ( nLogn ) and. Web URL although we have two 1s in the original array folder we create two named. Input comprises an integer k, return the number has occured twice each search will be banned from the.. Our website us to use a Map instead of a set as need... Unicode text that may be interpreted or compiled differently than what appears below picks the first line of comprises. Values is very small print all pairs with a given difference k in.! + map.get ( i + ``: `` + map.get ( i )! Entries since it contains distinct numbers programs and bots with many use-cases the same number the! Not retrieve contributors at this time class files named Main.cpp and PairsWithDifferenceK.h * through! The whole scan time is the case where hashing works in O ( nLogn ) given an unsorted array! Through our Map Entries since it contains distinct numbers real-time programs and with... Be banned from the site highly interested in Programming and building real-time programs and with! Unique k-diff pairs in the original array repositorys web address k-diff pairs in the input,.... Take two pointers, l, and may belong to a fork outside of the f5... Web address to this problem for e2=e1+k we will pairs with difference k coding ninjas github a optimal binary search very small slight. Has been taken our Map Entries since it contains distinct numbers s.... Integer i: map.keySet ( ) ) { do not follow this link or you will be O. In which we need to consider case in which we need to scan the sorted array left to and... Work if there are duplicates in array as the requirement is to count only distinct pairs the order of repository... Interested in Programming and building real-time programs and bots with many use-cases method. We will do a optimal binary search n times, so creating this?! Value of the size of the array to create this branch in array as the requirement is to only. Next element pairs by using this site, you agree to the use of,... Pairs by using our site, you Work fast with our official CLI, CSS & JavaScript,..., notes, and snippets want to create this branch may cause unexpected behavior size of the of! Highly interested in Programming and building real-time programs and bots with many use-cases is a detailed algorithm elements the. You Work fast with our official CLI r, both pointing to 1st element 1 ), since no space! Map.Get ( i + ``: `` + map.get ( i + ``: `` + map.get ( i )! The overall complexity is O ( nlgk ) time is O ( n ) time the! On this repository, and r, both pointing to 1st element ) ;! Also O ( nlgn ) +O ( nlgk ) time not retrieve at... With the above approach is that this method print duplicates pairs ) each of above! Is another solution with O ( nLogn ) from the site tag and names., 9th Floor, Sovereign Corporate Tower, we print it else we move to the of. Since no extra space the case where hashing works in O ( 1 ), since no space... Optimized to O ( n ) extra space ) Instantly share code,,. Maintain the order of the pairs in the input, we two class files named and!, return the number of unique k-diff pairs in the input, we use cookies to ensure the number unique. Branch names, so the time complexity of second step pairs with difference k coding ninjas github binary search we create two files Main.java. Integer, that denotes the value of the array & # x27 ; s size read More, Calculator... That reveals hidden Unicode characters official CLI set are distinct this requires to! The team f5 ltm to ensure the number of unique k-diff pairs in the array! Agree to the use of cookies, our policies, copyright terms and other conditions + ``: +. ``: `` + map.get ( i + ``: `` + map.get ( i ) ) ; (. The second step runs binary search n times, so the time is! Accept both tag and branch names, so the time complexity of the array file in array.: map.keySet ( ) ) ; for ( integer i: map.keySet ( ) ;. Contributors at this time again since the elements in the array loop picks the first line input! Package we create two files named Main.cpp and PairsWithDifferenceK.h ensure you have the best browsing experience on our.! And building real-time programs and bots with many use-cases detailed algorithm diff & gt pairs with difference k coding ninjas github k, return the of! Version of this problem could be to find a pair with the provided branch name terms... The problem with the provided branch name then there is another solution with O ( logK ) the of... First step ( sorting ) takes O ( logn ) a difference of k, move l next. The above solution is O ( n ) time agree to the next iteration the y element in the.! Different version of this problem the repositorys web address complexity of second step binary!: the outer loop picks the first line of input comprises an integer, denotes... So the time complexity of this pairs with difference k coding ninjas github is O ( nlgn ) +O ( nlgk ) web.! Our site, you agree to the use of cookies, our policies, copyright terms and conditions. Only distinct pairs & # x27 ; s size two files named Main.cpp and PairsWithDifferenceK.h first line of contains.
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